y=1/3x^2-4

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Solution for y=1/3x^2-4 equation: 


x in (-oo:+oo)

y = (1/3)*x^2-4 // - (1/3)*x^2-4

y-((1/3)*x^2)+4 = 0

(-1/3)*x^2+y+4 = 0

-1/3*x^2 = -(y+4) // : -1/3

x^2 = 3*(y+4)

x^2 = 3*(y+4) // ^ 1/2

abs(x) = 3^(1/2)*(y+4)^(1/2)

x = 3^(1/2)*(y+4)^(1/2) or x = -(3^(1/2)*(y+4)^(1/2))

x in { 3^(1/2)*(y+4)^(1/2), -(3^(1/2)*(y+4)^(1/2)) }

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